WebNov 16, 2011 · So you can store any integer in the range [decimal.MinValue, decimal.MaxValue] without losing any precision. If you want a wider range than that, you should use BigInteger as Fredrik mentioned (assuming you're on .NET 4, of course... I believe there are 3rd party versions available for earlier versions of .NET). Share … WebJan 19, 2015 · You cannot store more digits than will fit into the mantissa. The number of "supported" digits is, however, much larger, for example float will usually support up to …
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WebNov 27, 2013 · First, hopefully you recognize the issues with floating-point decimal representations.. 17774132 is equivalent to 1.7774132E7; the "E7" means it is being multiplied by 10^7.If your issue is that you want it displayed differently, you can use a NumberFormat.. Note that 17774132 is actually an integer and well below the threshold … WebSep 15, 2024 · The Long value can be assigned to the Decimal variable. The declaration for bigDec2 generates an overflow error because the value that's assigned to it is too large for Long. Because the numeric literal can't first be interpreted as a Long, it can't be assigned to the Decimal variable. grand lodge mount crested butte
MongoDB - What about Decimal type of value? - Stack Overflow
WebOct 28, 2016 · An 8 bit binary number can have 2^8 possible values or 2 * 2 * 2 * 2 * 2 * 2 * 2 * 2 or 256. That is to say, an 8 bit binary number can have values between 0 and 255 inclusive. If your requirement of "reasonable amount of decimals" falls within that range, then the type you are looking for is "uint8_t" or "char". WebSep 16, 2024 · 2 Answers Sorted by: 5 You can first multiply, then round like so: long val = (long) (6542.5699999999997 * 100000000 + 0.5); If the number can also be negative, you have to handle that case separately because the + 0.5 trick works only for positive values. Share Follow edited Sep 16, 2024 at 8:17 answered Sep 16, 2024 at 7:37 Henry 42.6k 7 … WebMay 5, 2015 · You have about 15 (almost 16) valid decimal digits in a double, and the rest of the 308 possible decimals are zeroes (actually undefined, but you can assume "zero" for better understanding). An unsigned long long only has 19 digits, but every single of them is exactly defined. EDIT: chinese food in the jar